Tuesday, October 24, 2017

877A. Alex and broken contest

/***

            Bismillahir Rahmanir Rahim
            Read the name of Allah, who created you!!!
            Author : Shah Newaj Rabbi Shishir
            Department of CSE, City University, Bangladesh.

***/

#include <bits/stdc++.h>
using namespace std;

#define sf scanf
#define pf printf
#define fast ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define scase sf ("%d",&tc)
#define sn sf ("%d",&n)
#define whilecase while (tc--)
#define eof while (cin >> n)
#define forloop for (pos=1; pos<=tc; pos++)
#define arrayloop (i=0; i<n; i++)
#define cinstr cin >> str
#define getstr getline (cin,str)
#define pcase pf ("Case %d: ",pos)
#define pii pair <int,int>
#define pb push_back
#define in insert
#define llu unsigned long long
#define lld long long
#define U unsigned int
#define endl "\n"

const int MOD = 1000000007;
const int MAX = 1000005;

int main (void)
{
    /*
    freopen ("input.txt","r",stdin);
    freopen ("output.txt","w",stdout);
    */
    char str[105];
    int len,i,k;

    while (sf("%s",str) != EOF)
    {
        k = 0;
        len = strlen(str);

        for (i=0; i<len; i++)
        {
            if (str[i] == '_')
                continue;

            if (str[i] == 'D' && str[i+1] == 'a' && str[i+2] == 'n' && str[i+3] == 'i' && str[i+4] == 'l')
            {
                i += 4;
                ++k;
            }
            else if (str[i] == 'O' && str[i+1] == 'l' && str[i+2] == 'y' && str[i+3] == 'a')
            {
                i += 3;
                ++k;
            }
            else if (str[i] == 'S' && str[i+1] == 'l' && str[i+2] == 'a' && str[i+3] == 'v' && str[i+4] == 'a')
            {
                i += 4;
                ++k;
            }
            else if (str[i] == 'A' && str[i+1] == 'n' && str[i+2] == 'n')
            {
                i += 2;
                ++k;
            }
            else if (str[i] == 'N' && str[i+1] == 'i' && str[i+2] == 'k' && str[i+3] == 'i' && str[i+4] == 't' && str[i+5] == 'a')
            {
                i += 5;
                ++k;
            }
        }

        if (k == 1)
            pf ("YES\n");
        else
            pf ("NO\n");
    }

    return 0;
}

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